Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 50)
50.
If two bodies having masses m1 and m2 (m1>m2) have equal kinetic energies, the momentum of body having mass m1 is __________ the momentum of body having mass m2.
Discussion:
32 comments Page 1 of 4.
Lokesh said:
1 decade ago
K.E. = 1/2mv^2.
.
. . v1 = v2.
Momentum = mv.
So, m1v1 > m2v2.
.
. . v1 = v2.
Momentum = mv.
So, m1v1 > m2v2.
Dev said:
1 decade ago
How came m1v1 is greater?
Suresh kumawat said:
1 decade ago
How can you say that v1 = v2.
(1)
Deep said:
1 decade ago
1/2 m1 v1^2 = 1/2 m2 v2^2.
As m1>m2 So v2 must be >v1.
m1.v1/m2.v2=v2/v1 will have value greater than 1. So m1.v1>m2.v2.
As m1>m2 So v2 must be >v1.
m1.v1/m2.v2=v2/v1 will have value greater than 1. So m1.v1>m2.v2.
(1)
Harish said:
1 decade ago
@Suresh.
Given, K.E1 = K.E2, also m1>m2, K.E1 = 1/2m1v1^2, K.E2 = 1/2m2v2^2.
In order to get both the KE equal, their Velocity should be equal since m1>m2 (given). Therefore, Momentum, m1v1 > m2v2.
Given, K.E1 = K.E2, also m1>m2, K.E1 = 1/2m1v1^2, K.E2 = 1/2m2v2^2.
In order to get both the KE equal, their Velocity should be equal since m1>m2 (given). Therefore, Momentum, m1v1 > m2v2.
(1)
Ambarish said:
1 decade ago
1/2m1(v1)^2 = 1/2m2(v2)^2.
= m1(v1)^2 = m2(v2)^2.
= m1(v1)^2/m2(v2)^2 = 1.
= (v1)^2/(v2)^2 is greater than 1(science m1/m2 is greater than 1).
= v1^2is greater than v2^2.
= v1 is greater than v2.
So, m1v1 is greater than m2v2.
= m1(v1)^2 = m2(v2)^2.
= m1(v1)^2/m2(v2)^2 = 1.
= (v1)^2/(v2)^2 is greater than 1(science m1/m2 is greater than 1).
= v1^2is greater than v2^2.
= v1 is greater than v2.
So, m1v1 is greater than m2v2.
Gaurav said:
1 decade ago
Consider m1 = 4, v1 = 2, m2 = 1, v2 = 4.
Here m1v1>m2v2 :).
Here m1v1>m2v2 :).
Kingshuk said:
1 decade ago
@Harish.
You are wrong. Velocities can not be equal in order to attain equal K. E where m1>m2.
You are wrong. Velocities can not be equal in order to attain equal K. E where m1>m2.
Sasi said:
1 decade ago
Momentum = Mass*Velocity.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Sasi said:
1 decade ago
Momentum = Mass*Velocity.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
Here (mass) m1>m2.
Hence momentum of body 1 is greater than the body 2.
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