Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 14)
14.
In a framed structure, as shown in the below figure, the force in the member BC is
Discussion:
14 comments Page 1 of 2.
Humayoun said:
4 years ago
By lamis theorem W/sin60 = BC/sin90 so BC equals to +2W/√3 (tensile).
Or
By resolving BC vertically and applying the equilibrium equation in the vertical direction we get
BCsin60 - W = 0.
BC= +2W/√3 (tensile).
Or
By resolving BC vertically and applying the equilibrium equation in the vertical direction we get
BCsin60 - W = 0.
BC= +2W/√3 (tensile).
(1)
K910 said:
5 years ago
It is very easy to divide the section into half shift the load w (you can shift the load) to the right side and make a right angle triangle where perpendicular CE I assume make (w) and base as EB = cos60 and hypotenuse is BC= sin60 - w and for equilibrium, BC = sin60 - w =0 BC= +w/ (root3/2) = 2/w root3 assign is +ve so it is tensile.
Sourav mondal said:
6 years ago
Please explain.
Rupesg said:
6 years ago
Please, anyone, explain the answer in detail to get it.
Zeeshan bashir said:
6 years ago
It's in compression, according to methods of joints.
Namita nami said:
6 years ago
I am not getting this, please explain briefly.
Kishan Prajapati said:
7 years ago
Explain Lamis theorem.
Gaurav phalke said:
7 years ago
See here When you resolve force at point B,
then you get,
IF we get the force at away from B.
x=BC cos60=0.
y=BC sin60-w=0.
BC=2*W/3.
HERE YOU GET YOUR ANSWER TENSILE.
then you get,
IF we get the force at away from B.
x=BC cos60=0.
y=BC sin60-w=0.
BC=2*W/3.
HERE YOU GET YOUR ANSWER TENSILE.
Salman said:
8 years ago
It is By Lami theorem.
(1)
Harsh said:
9 years ago
BC is compressive right but CB is?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers