Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 14)
14.
In a framed structure, as shown in the below figure, the force in the member BC is
Discussion:
14 comments Page 1 of 2.
Aftab Alam said:
9 years ago
How we came to know that it is tensile or compressive by Lami's theorem?
(1)
Salman said:
8 years ago
It is By Lami theorem.
(1)
Humayoun said:
4 years ago
By lamis theorem W/sin60 = BC/sin90 so BC equals to +2W/√3 (tensile).
Or
By resolving BC vertically and applying the equilibrium equation in the vertical direction we get
BCsin60 - W = 0.
BC= +2W/√3 (tensile).
Or
By resolving BC vertically and applying the equilibrium equation in the vertical direction we get
BCsin60 - W = 0.
BC= +2W/√3 (tensile).
(1)
Dilip verma said:
1 decade ago
By lami theorem, w/sin60 = BC/sin90.
Therefore BC= 2W/ROOT3.
Therefore BC= 2W/ROOT3.
K.vengal reddy said:
1 decade ago
Given angle at B is 60 and weight W is acting downwards which experiences tension. So a\c to Lami formula W/sin60 gives 2W/root3 on simplification.
Mohd Mujtaba said:
9 years ago
Apply Law of Sine and get the answer.
Harsh said:
9 years ago
BC is compressive right but CB is?
Gaurav phalke said:
7 years ago
See here When you resolve force at point B,
then you get,
IF we get the force at away from B.
x=BC cos60=0.
y=BC sin60-w=0.
BC=2*W/3.
HERE YOU GET YOUR ANSWER TENSILE.
then you get,
IF we get the force at away from B.
x=BC cos60=0.
y=BC sin60-w=0.
BC=2*W/3.
HERE YOU GET YOUR ANSWER TENSILE.
Kishan Prajapati said:
7 years ago
Explain Lamis theorem.
Namita nami said:
6 years ago
I am not getting this, please explain briefly.
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