Logical Reasoning - Number Series - Discussion

Find the number that fits somewhere into the middle of the series. Some of the items involve both numbers and letters

3. 

Look at this series: V, VIII, XI, XIV, __, XX, ... What number should fill the blank?

[A]. IX
[B]. XXIII
[C]. XV
[D]. XVII

Answer: Option D

Explanation:

This is a simple addition series; each number is 3 more than the previous number.

Karthi said: (Jul 24, 2010)  
i canot understand this sum.......

Venkata Naidu said: (Feb 23, 2011)  
This is Roman letter series.

Samiran Dasgupta said: (Jun 16, 2011)  
Please clarify more about the answer

Jigar N.Madhu said: (Jun 18, 2011)  
1=I 2=II 3=III 4=IV 5=V 6=VI 7=VII 8=VIII 9=IX 10=X

now each number is 3 more than the previous number
i hope your doubt has been solved ...

Mohan said: (Aug 11, 2012)  
I know that:.

1=I.
2=II.
3=III.
4=IV.
5=V.
6=VI.
7=VII.
8=VIII.
9=IX.
10=X.

& so on.
Therefore the given numbers are:.

5, 8, 9, 14, __, 20.

But I can't understand the explanation that each number is 3 more than the previous number because by this way.

5+3=8.

But 8+3 isn't equal to 9,

Similarly, 9+3 isn't equal to 14.

So how is it possible that the option [D] i.e. XVII (no. 17) is the correct answer.

Skyz said: (Dec 2, 2013)  
Mohon, you made a mistake.

XI = 11, not 9 (which is IX).

Look at the question again. series will be : 5, 8, 11, 14, __, 20.

Prashanthi said: (Dec 8, 2013)  
Its simple process:

5+3 = 8.
8+3 = 11.
11+3 = 14.
14+3 = 17.
17+3 = 20.

Soo here in the series 5,8,11,14,20 missing number is 17 so the ans is 17.

Uma said: (Apr 16, 2015)  
I agree with @Skyz which xvii is 17+3=20(xx).

Ramu said: (May 16, 2015)  
1= I.
2 = II.
3 = III.
4 = IV.
5 = V.
6 = VI.
7 = VII.
8 = VIII.
9 = IX.
10 = X.
11 = XI.
12 = XII.
13 = XIII.
14 = XIV.
15 = XV.
16 = XVI.
17 = XVII.
18 = XVIII.
19 = XIX.
20 = XX.
21 = XXI.
22 = XXII.
23 = XXIII.
24 = XXIV.

This is the series.

5, 8, 9, 14, __, 20.

5+3 = 8.
Add +3.
14+3 = 17.

So 17 roman value is.

Gunjan said: (Sep 6, 2015)  
I agree with the answer but I do not understand "each no is 3 more than previous no". Logic is used here is:

Series:

5, 8, 11, 16, ?, 20.

Hence answer has to be between 16 & 20. Here only option available was 17 which is option D.

Abhinav Khandelwal said: (Feb 25, 2016)  
I 1.
II 2.
III 3.
IV 4.
V 5 1st.
VI 6.
VII 7.
VIII 8 2nd.
IX 9.
X 10.
XI 11 3rd.
XII 12.
XIII 13.
XIV 14 4th.
XV 15.
XVI 16.
XVII 17.
XVIII 18.
XIX 19.
XX 20 6th.

VTH and VIII number difference is 2, XI and XIV number difference is 2.

So, D is the right answer.

Because dumber difference is 2.

Utkarsh said: (May 28, 2016)  
Simple and easy. Thank you.

Nikhitha said: (Dec 28, 2016)  
Thank you all for the great explanation.

Vedvik said: (Jan 26, 2017)  
Here roman convert in no ...that mean - 5, 8, 9, 14, ?, 20.

i.e, 5 * 2 = 10 - 1 = 9
8 * 2 = 16 - 2 = 14
9 * 2 = 18 - 1 = 17.

Mansi Chhabra said: (Sep 21, 2017)  
As 5, 8, 11. 14, . , 20 so as from 5 and 8 there is difference of 3 and the same follows 8 and 11 also it means each number has the difference of 3 so after 14 if we will add 3 to it we will get 17 means (d) is the option.

Sanamdeep Singh said: (Aug 31, 2021)  
It's in the order of 5, 8, 11, 14, 17, 20.

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