Logical Reasoning - Number Series - Discussion
Discussion Forum : Number Series - Type 4 (Q.No. 3)
Directions to Solve
Find the number that fits somewhere into the middle of the series. Some of the items involve both numbers and letters
3.
Look at this series: V, VIII, XI, XIV, __, XX, ... What number should fill the blank?
Answer: Option
Explanation:
This is a simple addition series; each number is 3 more than the previous number.
Discussion:
16 comments Page 1 of 2.
ABHINAV KHANDELWAL said:
10 years ago
I 1.
II 2.
III 3.
IV 4.
V 5 1st.
VI 6.
VII 7.
VIII 8 2nd.
IX 9.
X 10.
XI 11 3rd.
XII 12.
XIII 13.
XIV 14 4th.
XV 15.
XVI 16.
XVII 17.
XVIII 18.
XIX 19.
XX 20 6th.
VTH and VIII number difference is 2, XI and XIV number difference is 2.
So, D is the right answer.
Because dumber difference is 2.
II 2.
III 3.
IV 4.
V 5 1st.
VI 6.
VII 7.
VIII 8 2nd.
IX 9.
X 10.
XI 11 3rd.
XII 12.
XIII 13.
XIV 14 4th.
XV 15.
XVI 16.
XVII 17.
XVIII 18.
XIX 19.
XX 20 6th.
VTH and VIII number difference is 2, XI and XIV number difference is 2.
So, D is the right answer.
Because dumber difference is 2.
(6)
Vedvik said:
9 years ago
Here roman convert in no ...that mean - 5, 8, 9, 14, ?, 20.
i.e, 5 * 2 = 10 - 1 = 9
8 * 2 = 16 - 2 = 14
9 * 2 = 18 - 1 = 17.
i.e, 5 * 2 = 10 - 1 = 9
8 * 2 = 16 - 2 = 14
9 * 2 = 18 - 1 = 17.
(2)
Mansi chhabra said:
8 years ago
As 5, 8, 11. 14, . , 20 so as from 5 and 8 there is difference of 3 and the same follows 8 and 11 also it means each number has the difference of 3 so after 14 if we will add 3 to it we will get 17 means (d) is the option.
(2)
Sanamdeep singh said:
4 years ago
It's in the order of 5, 8, 11, 14, 17, 20.
(2)
Nikhitha said:
9 years ago
Thank you all for the great explanation.
(1)
Karthi said:
2 decades ago
i canot understand this sum.......
Venkata naidu said:
1 decade ago
This is Roman letter series.
Samiran dasgupta said:
1 decade ago
Please clarify more about the answer
Jigar n.madhu said:
1 decade ago
1=I 2=II 3=III 4=IV 5=V 6=VI 7=VII 8=VIII 9=IX 10=X
now each number is 3 more than the previous number
i hope your doubt has been solved ...
now each number is 3 more than the previous number
i hope your doubt has been solved ...
Mohan said:
1 decade ago
I know that:.
1=I.
2=II.
3=III.
4=IV.
5=V.
6=VI.
7=VII.
8=VIII.
9=IX.
10=X.
& so on.
Therefore the given numbers are:.
5, 8, 9, 14, __, 20.
But I can't understand the explanation that each number is 3 more than the previous number because by this way.
5+3=8.
But 8+3 isn't equal to 9,
Similarly, 9+3 isn't equal to 14.
So how is it possible that the option [D] i.e. XVII (no. 17) is the correct answer.
1=I.
2=II.
3=III.
4=IV.
5=V.
6=VI.
7=VII.
8=VIII.
9=IX.
10=X.
& so on.
Therefore the given numbers are:.
5, 8, 9, 14, __, 20.
But I can't understand the explanation that each number is 3 more than the previous number because by this way.
5+3=8.
But 8+3 isn't equal to 9,
Similarly, 9+3 isn't equal to 14.
So how is it possible that the option [D] i.e. XVII (no. 17) is the correct answer.
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