General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 38)
38.
The ionic radii of N3-, O2-, F- and Na+ follows the order
Discussion:
14 comments Page 1 of 2.
Padma said:
1 decade ago
Positively charged ion has less ionic radius than negatively charged ion.
Mr.D said:
1 decade ago
Across the period, ionic radii decreases.
Rajesh said:
1 decade ago
When the negative charge increases that means the number of outer most electrons are also increases that cause more repulsion and that results significant increase in ionic radius that exactly adverse to positive ions.
Subhash jha said:
1 decade ago
In respect to the electron in atom as electron density decrease in the atom the ionic radii decrease.
Jimmy said:
1 decade ago
Which have higher proton, have less ionic radii. Na+ have 11 proton and N3- have 7 proton.
Sumanta Kumar Nayak said:
1 decade ago
Due to isoelectronic of all atom. The no.of electrons are same. So the lower atomic no. Atom has greater in ionic radii. So the order is follows sa type in A.
Bikash Ranjan Parhi said:
1 decade ago
N3-, O2-, F- and Na+ are isoelectronic ions. When the negative charge increases, the number of outer most electrons are also increases and added to the new shells of that particular ions which causes the increase in ionic radius.
So the order of ionic radii is in the following order;
N3- > O2- > F- > Na+.
So the order of ionic radii is in the following order;
N3- > O2- > F- > Na+.
Md Tauhid said:
1 decade ago
Greater the value of zeff lower the radii so Na has higher zeff, so lower radii.
Savita said:
10 years ago
For the completion of octet atom loses e- forms negative ion, so size is small. When gains e-forms positive ion, so size is large. Cation having large size than anion.
Yusuf said:
9 years ago
Since the element is in the same period, so ionic radii increase.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers