General Knowledge - Chemistry - Discussion

Discussion Forum : Chemistry - Section 1 (Q.No. 38)
38.
The ionic radii of N3-, O2-, F- and Na+ follows the order
N3- > O2- > F- > Na+
N3- > Na+ > O2- > F-
Na+ > O2- > N3- > F-
O2- > F- > Na+ > N3-
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
14 comments Page 1 of 2.

Mahwish said:   5 years ago
The more negative charge on the non-metal ions the more they will increase in size.

Sonu soona said:   5 years ago
Ionics radii = 1/size.

Samrat said:   7 years ago
When sodium loses one electron it acquires neon configuration.

And as we know that noble gases are measured in terms of Vanderwall's radius surely it is of greater value compared to others.

Sunitha said:   8 years ago
As negative charge increases ionic radii increases.

Yusuf said:   9 years ago
Since the element is in the same period, so ionic radii increase.

Savita said:   10 years ago
For the completion of octet atom loses e- forms negative ion, so size is small. When gains e-forms positive ion, so size is large. Cation having large size than anion.

Md Tauhid said:   1 decade ago
Greater the value of zeff lower the radii so Na has higher zeff, so lower radii.

Bikash Ranjan Parhi said:   1 decade ago
N3-, O2-, F- and Na+ are isoelectronic ions. When the negative charge increases, the number of outer most electrons are also increases and added to the new shells of that particular ions which causes the increase in ionic radius.

So the order of ionic radii is in the following order;

N3- > O2- > F- > Na+.

Sumanta Kumar Nayak said:   1 decade ago
Due to isoelectronic of all atom. The no.of electrons are same. So the lower atomic no. Atom has greater in ionic radii. So the order is follows sa type in A.

Jimmy said:   1 decade ago
Which have higher proton, have less ionic radii. Na+ have 11 proton and N3- have 7 proton.


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