Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 2)
2.
Using the basic trigonomic functions, determine the length of side AB of the right triangle.
Discussion:
35 comments Page 3 of 4.
Daulu Reve said:
1 decade ago
sin45=AB/AC
sin45=AB/10
AB=sin45*10
AB=7.07
sin45=AB/10
AB=sin45*10
AB=7.07
Md.AminurRahman said:
9 years ago
Sine45 degree = AB\10.
AB = 7.07 => Answer.
AB = 7.07 => Answer.
Sanket kamble pce said:
9 years ago
Sin 45 = AB/10.
0.707 * 10 = AB.
AB = 7.07.
0.707 * 10 = AB.
AB = 7.07.
ASHOK said:
1 decade ago
AB=BC*AC
AB=SIN45*10
=0.707*10
AB=7.07
AB=SIN45*10
=0.707*10
AB=7.07
Mani said:
1 decade ago
Sin 45 = AB/10.
0.707*10 = AB.
AB = 7.07.
0.707*10 = AB.
AB = 7.07.
AJIT BANNE BEC BAGALKOT said:
1 decade ago
AB = ACsin45
AB = 10*0.707
AB = 7.07
AB = 10*0.707
AB = 7.07
Darshan Deore said:
1 decade ago
Sin45 = AB/10.
0 = AB/10.
AB = 7.07.
0 = AB/10.
AB = 7.07.
Nagaraju said:
1 decade ago
Sin45 value = 1/1.414 = 0.707213579
RATHOD VISHAL said:
1 decade ago
sin45=AB/10
.707=AB/10
AB=7.07
.707=AB/10
AB=7.07
Ramji said:
1 decade ago
sin45 = 0.70
0.70*10 = 7.07
0.70*10 = 7.07
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