Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 2)
2.
Using the basic trigonomic functions, determine the length of side AB of the right triangle.
Discussion:
35 comments Page 2 of 4.
Lokesh said:
1 decade ago
hyp^2=opp^2+adj^2
10^2=x^+x^2(opp=adj=x,isosceles triangle)
height(h)=x=7.07
10^2=x^+x^2(opp=adj=x,isosceles triangle)
height(h)=x=7.07
Prakash said:
1 decade ago
sin theta=opp. side/hyp.
sin45=AB/10
.707=AB/10
AB=.707*10
AB=7.07
sin45=AB/10
.707=AB/10
AB=.707*10
AB=7.07
Prem said:
1 decade ago
Sin 45 = AB/AC
so, AB = AC x Sin45
AB = 10 x Sin 45
AB = 7.07
so, AB = AC x Sin45
AB = 10 x Sin 45
AB = 7.07
BEPO said:
1 decade ago
sin 45=AB/AC
1/2^2=AB/10
10* 1/1.4142=AB/10
10* 0.707=AB
7.07=AB
1/2^2=AB/10
10* 1/1.4142=AB/10
10* 0.707=AB
7.07=AB
Madan said:
1 decade ago
Sin45=ab/ac
where ac=10
then ab=sin45*ac
ab=.707*10
ab=7.07
where ac=10
then ab=sin45*ac
ab=.707*10
ab=7.07
G.kavipandi said:
1 decade ago
AB=sin theta * x .it direct formula to find distance in em
ASHUTOSH said:
1 decade ago
sin(45) = AB/10.
AB = 10sin(45).
AB = 10^0.707.
AB = 7.07.
AB = 10sin(45).
AB = 10^0.707.
AB = 7.07.
Sunil mlaviya said:
1 decade ago
sin 45 = ab/10.
(sin 45 = 0.07)
ab = .07x10.
ab = 7.07.
(sin 45 = 0.07)
ab = .07x10.
ab = 7.07.
Jai Praksh Singh said:
1 decade ago
Sin 45 = AB/AC =AB/10
AB = .0707X10 = 7.07
AB=7.07
AB = .0707X10 = 7.07
AB=7.07
Anisha said:
1 decade ago
How to calculate hypotenuse of a right triangle?
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