Electronics - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 10)
10.
Which component is shorted?


Discussion:
49 comments Page 4 of 5.
Priya said:
1 decade ago
@Cee.
Explains that current is highest in R4 but it is a obvious thing that current should be low in I4 because R4 = 12/R4.
Explains that current is highest in R4 but it is a obvious thing that current should be low in I4 because R4 = 12/R4.
Ravi said:
1 decade ago
Short circuit means high circuit current. High circuit means low resistance.
Bhadmanathan.c said:
1 decade ago
As we all know, voltage is constant in parallel circuit. So I = V/R.
Current through R1 = 12mA.
Similarly through R2, R3 and R4 is 6mA, 4mA and 3mA.
Open circuit = No current or less current flows.
Short circuit = Large current flows.
Here R4 has Max current flow. So it would be short circuited.
Current through R1 = 12mA.
Similarly through R2, R3 and R4 is 6mA, 4mA and 3mA.
Open circuit = No current or less current flows.
Short circuit = Large current flows.
Here R4 has Max current flow. So it would be short circuited.
Vishnu said:
10 years ago
A galvanometer is a very sensitive meter which is used to measure tiny currents, usually 1 mA or less. And its symbol is different there is no image shows that current is passing through R4 or R4 act as a load better is to put a volt meter across every resistor to show that the current is passing through to simplify the question.
Ravi said:
10 years ago
Guys, they are asking which of these resistors is faulty (thus creating a shorted path) and they have shown us that no current flows through first three resistors, that means R4 is shorted.
Kevin said:
10 years ago
The way I made sense of this problem is to think of the battery as a voltage source with and internal series resistor not shown.
Short circuit current is 2.4 amps Internal series resistance can be calculated, R=I/V, R=2.4 amps/12 Volts = 0.2 ohms.
The only way to get all 4 ammeters to read 2.4 amps is for R4 to be shorted.
Short circuit current is 2.4 amps Internal series resistance can be calculated, R=I/V, R=2.4 amps/12 Volts = 0.2 ohms.
The only way to get all 4 ammeters to read 2.4 amps is for R4 to be shorted.
Rashmi said:
10 years ago
If negative terminal of g is connected to battery it don't mean that the g is shorted.
Mamta said:
9 years ago
As per @Bhadmanathan:
As we all know, voltage is constant in parallel circuit. So I = V/R.
Current through R1 = 12 mA.
Similarly through R2, R3 and R4 is 6 mA, 4 mA and 3 mA.
Open circuit = No current or less current flows.
Short circuit = Large current flows.
But Large current flow is through. So how can R4 short circuit?
As per this rule R1 should be short circuited as low resistance is R1.
As we all know, voltage is constant in parallel circuit. So I = V/R.
Current through R1 = 12 mA.
Similarly through R2, R3 and R4 is 6 mA, 4 mA and 3 mA.
Open circuit = No current or less current flows.
Short circuit = Large current flows.
But Large current flow is through. So how can R4 short circuit?
As per this rule R1 should be short circuited as low resistance is R1.
Mamta Bisht said:
9 years ago
Short circuit means lower the resistance. So R1 has the lower resistance so R1 should be the answer.
Shivanand said:
9 years ago
Very simple just observe that all galvanometers are reading the same current there id is no current which is flowing through the r1 r2 r3 and at last to form the loop so that current can flow r4 must be short circuited.
(1)
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