# Electronics - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - General Questions (Q.No. 10)
10.
Which component is shorted?

R1
R2
R3
R4
Explanation:
No answer description is available. Let's discuss.
Discussion:
49 comments Page 3 of 5.

Akshay Prakash said:   1 decade ago
G stands for Galvanometer here i suppose, that's why 'A' is written by its side to show that it is being used an ammeter.
& since current is same in all branches therefore,r1,r2,r3 are open and only r4 is in circuit..

Here G stands for galvanometer itself. But 2.400G doesn't mean that the current in branch is 2.400GA. It just indicate the strength of galvanometer up to which it can measure the current. Since all the resistors are in parallel and the circuit acts as current divider more current flows from 1kohm and the rest is divide among others r4 gets less amount of current showing high resistance and low conductance. In general short circuit is nothing but the path for current having low impedance (high conductance) so the component which should be shorted should be r1.

Pankaj answer is the best explained. See the value all the galvanometer is same. It tells that current is not passing through R1, R2, R3. The entire current 2. 400A is passing through R4.

Last two Components are Shorted. Because of no junction point is there.

Hey guys G is not a Conductance if its conductance means they denote it as (mho) not by G we have to use its unit only after the values not variables its galvanometer I agree wit pankaj he is right G is galvanometer and it measure current. 2.4 A is in the next G so no current through the R1. Similarly, no current through R2, R3 and finally whole current through R4. So R4 is short circuited and others are open circuit.

Monali Trivedi said:   1 decade ago
@P.Jayeshkumar.

I think each and every component has same junction point.

Imbesat alam said:   1 decade ago
G is conductance and it is related to resistance as R=1/G.

Man singh said:   1 decade ago
'A' in the box of 2.400 G confirms that it is Galvanometer.

Now since ammeter is connected in series & zero resistance is assumed offered by ammeter. So while solving we can ignore/ discard the galvanometer(ammeter) & redraw the circuit & then Solve it.

Total I = 25mA.

I1 Across R1 = 12mA.
I2 Across R2 = 6mA.
I3 Across R3 = 4mA.
I4 Across R4 = 1mA.

Recheck Total I = (I1+I2+I3+I4) = 25mA;

Short circuit means more current flows; while open circuit means no current flows or less current flows.

Max current is flowing through R1 & less through R4.

Basically current is flowing though all Resistances. Also Rating of Galvanometer is 2.4 that is much higher than 25mA (Total current) hence all Galvanometer are in working condition again confirming that current is flowing through all Resistances.

I would like to conclude that R1 is comparatively short circuit. But we all are trying to justify R4 because R4 is the option given in the answer series.