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Electronics - Field Effect Transistors (FET) - Discussion

Discussion Forum : Field Effect Transistors (FET) - General Questions (Q.No. 7)
Field Effect Transistors (FET)
7.
In the constant-current region, how will the IDS change in an n-channel JFET?
As VGS decreases ID decreases.
As VGS increases ID increases.
As VGS decreases ID remains constant.
As VGS increases ID remains constant.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 2 of 2.
Aarth said:   1 decade ago
Both A and D are correct as for me. Because in constant region Ids remains constant till breakdown region occurs.
Sri said:   6 years ago
The pinch-off voltage for an N-channel JFET is 4V. When VGS=1V, lVDS(min)l at which pinch-off occurs is equal to
(1)
Abu Sayeed said:   1 decade ago
Answer is 1.

As channel depends on Vgs and Ids depends on channel. So we can say Ids is proportional to Vgs.
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