Electronics - Field Effect Transistors (FET) - Discussion
Discussion Forum : Field Effect Transistors (FET) - General Questions (Q.No. 7)
7.
In the constant-current region, how will the IDS change in an n-channel JFET?
Discussion:
13 comments Page 2 of 2.
Vardaman said:
9 years ago
In n channel vgs is negative if vgs increase in more -ve I'd decrease. But vgs decrease I'd automatically increase.
Pankky said:
8 years ago
Answer is correct because characteristic plot between Id and Vds so that according to this if Vds increases then id remains constant.
But here if we want to decrease the current Id then Vgs will be decreased.
But here if we want to decrease the current Id then Vgs will be decreased.
Mohan said:
8 years ago
Option D is correct.
In according to the JFET graph,
1.Linear region
2.Pinch off region
3.Cutt off region
1.Linear region - Gate source voltage increases the drain current also increases.
2.Pinch off region - In which gate-source voltage, the drain current become zero the voltage is known as pinch off.
3.Cutt off region - After the pinch-off region the gate is not dependent the gate-source voltage.
In according to the JFET graph,
1.Linear region
2.Pinch off region
3.Cutt off region
1.Linear region - Gate source voltage increases the drain current also increases.
2.Pinch off region - In which gate-source voltage, the drain current become zero the voltage is known as pinch off.
3.Cutt off region - After the pinch-off region the gate is not dependent the gate-source voltage.
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