Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - General Questions (Q.No. 9)
9.
What is the current through the LED?
Discussion:
35 comments Page 1 of 4.
Ganesh.K said:
1 decade ago
I = V/R
R = 330 , V = 6 - 1.5V (LED drop voltage) So V = 4.5V
I = 4.5/330
I = 0.013 A or 13 mA
R = 330 , V = 6 - 1.5V (LED drop voltage) So V = 4.5V
I = 4.5/330
I = 0.013 A or 13 mA
Ganesh.s said:
1 decade ago
For what 1.5v is subtract from the 6v ..?if the led drop voltage did't not given then .how it will subtract..?
Ganesh P said:
1 decade ago
LED voltage drop is 1.5V..... U need to remind this..
Prasath said:
1 decade ago
Thanx for reminding the LED drop voltage Ganesh S
Nithesh said:
1 decade ago
Why 6 - 1. 5 ?
Devidas K said:
1 decade ago
No. Led having its own resistance that is self resistance so some voltage must be drop across it.
Answer is correct.
Answer is correct.
Rajesh said:
1 decade ago
Thanks for reminding that led IR drop.
DEV said:
1 decade ago
Is all type of LED has the same voltage drop?
Akash tanna said:
1 decade ago
There is not any single device which have't any resistance and it is having some resistance then due to the currrent passing loss will be generated on the bases of I2R losses equation.
Akanksha said:
1 decade ago
Can anybody tell me what will be the result if LED is inverted. Will the led drop voltage add to 6V. ? it was asked me in my practical exam.
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