Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - General Questions (Q.No. 9)
9.
What is the current through the LED?
Discussion:
35 comments Page 4 of 4.
Gokul said:
7 years ago
Good explanation, thanks all.
Pavithra said:
6 years ago
Good explanation. Thanks to all.
Jyoti prasad said:
6 years ago
In series, the current remains the same.
So I = V1/R1 = 6/330 = 18 mA.
So I = V1/R1 = 6/330 = 18 mA.
(3)
M.lakshmireddy said:
5 years ago
The lead voltage drop is 1.5 v.
(2)
Engr Riri said:
3 years ago
Approx. Voltage @LED (red) = 1.7V.
(6V - 1.7V)/330 ohms = 13.03mA.
(6V - 1.7V)/330 ohms = 13.03mA.
(4)
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