Electronics - Diodes and Applications - Discussion
Discussion Forum : Diodes and Applications - General Questions (Q.No. 9)
9.
What is the current through the LED?
Discussion:
35 comments Page 1 of 4.
Engr Riri said:
3 years ago
Approx. Voltage @LED (red) = 1.7V.
(6V - 1.7V)/330 ohms = 13.03mA.
(6V - 1.7V)/330 ohms = 13.03mA.
(4)
Jyoti prasad said:
6 years ago
In series, the current remains the same.
So I = V1/R1 = 6/330 = 18 mA.
So I = V1/R1 = 6/330 = 18 mA.
(3)
M.lakshmireddy said:
5 years ago
The lead voltage drop is 1.5 v.
(2)
Surendra said:
1 decade ago
LEDcolour Forward voltage (volt).
1. Infrared 1.3 to 1.5.
2. Red 1.5 to 1.8.
3. Yellow 2 to 2.2.
4. Green 2.2 to 2.4.
5. Blue 3 to 5.
1. Infrared 1.3 to 1.5.
2. Red 1.5 to 1.8.
3. Yellow 2 to 2.2.
4. Green 2.2 to 2.4.
5. Blue 3 to 5.
(1)
Ravi Shankar Kumar said:
1 decade ago
If you don't remember the forward voltage of the LED then use simple common sense that if that(LED) is not there then current in the circuit will be 18mA so if it is present then current must be lesser than 18mA because of resistance offered by LED ,only option is 13mA which is lesser than 18mA :P
(1)
Raja said:
1 decade ago
Is somebody ask how do we know on which color led it is then?
Ganesh.s said:
1 decade ago
For what 1.5v is subtract from the 6v ..?if the led drop voltage did't not given then .how it will subtract..?
Ganesh P said:
1 decade ago
LED voltage drop is 1.5V..... U need to remind this..
Prasath said:
1 decade ago
Thanx for reminding the LED drop voltage Ganesh S
Pavithra said:
6 years ago
Good explanation. Thanks to all.
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