Electronics and Communication Engineering - Networks Analysis and Synthesis
Exercise : Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 27
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 2
26.
If operator 'a' = 1 ∠120° then (1 + a2) =
Answer: Option
Explanation:
1 - a2 = 1 + 0.5 + j 0.866 = 3∠30°.
27.
Two 2 port circuits are connected cascaded. To determine the response, it is more convenient to use
Answer: Option
Explanation:
ABCD matrix of two-four terminal network is the product of individual ABCD matrices.
28.
In the circuit of figure. The current supplied by battery at t = ∞ is
Answer: Option
Explanation:
At t = ∞, inductance is short-circuited and capacitor is open circuited.
29.
The natural frequency Sn of the given circuit is
Answer: Option
Explanation:
[When current open and seen from inductance side]
Sn + 1 = 0 
Sn = -1.
30.
For addition and subtraction operations, phasors
Answer: Option
Explanation:
Addition and subtraction is not possible in polar form.
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