Electronics and Communication Engineering - Networks Analysis and Synthesis
Exercise : Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 27
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 2
46.
A source of angular frequency 1 rad sec has a source impedance consisting of 1 Ω resistance in series with 1 H inductance. The load that will obtained the maximum power transfer is
Answer: Option
Explanation:
According to question Z = R + jωL
ω = 1, L = 1 
Z = R + j
max. power transfer will take place when Z = R - j C = 1.
47.
When tracing through a resistance we always get a voltage drop.
Answer: Option
Explanation:
It depends on direction of current.
48.
A copper coil has a resistance of 40 ohm at 20°C. At 100°C the resistance is likely to be
Answer: Option
Explanation:
Temperature coefficient of copper = 0.00393
R100 = 40 (1 + 0.00393 x 80) 
54 Ω
49.
Assertion (A): In a parallel circuit with three branches having R, L and C respectively and fed by a step current I, the current through inductance is always zero.
Reason (R): The time constant of R-L circuit is L/R.
Answer: Option
Explanation:
The current through inductance is zero at t = 0 and equal to I at t = ∞.
50.
When a source is delivering maximum power to a load through a network, the ratio of power delivered to the source power
Answer: Option
Explanation:
The network can be replaced by Thevenin's equivalent circuit. The load gets maximum power from the network but Thevenin's theorem does not guarantee that this will be half of maximum power.
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