Electronics and Communication Engineering - Networks Analysis and Synthesis
Exercise : Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 27
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 2
41.
The current in an RL series circuit is 1 - e-t amperes. Then di/dt is
Answer: Option
Explanation:
= 0 - (-e-t) = e-t.
42.
Given
, and f(t)t → ∞ is
. The value of k is


Answer: Option
Explanation:
.
43.
In a one port network
. It is excited by a unit step current. The initial and final values of voltage across the network impedance are

Answer: Option
Explanation:
44.
In the circuit of figure, the current through battery E2 is


Answer: Option
Explanation:
1 A current is flowing into the battery. Therefore, it is charging current.
45.
In figure, the current supplied by battery at t = 0.5s is


Answer: Option
Explanation:
Time constant of R-L branch = = 0.5 seconds. Current in 6Ω resistance is 1 A and current in R-L branch is 63.2% of final current of 1 A.
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