Electronics and Communication Engineering - Networks Analysis and Synthesis

41.
The current in an RL series circuit is 1 - e-t amperes. Then di/dt is
1 - e-t
- e-t
et
e-2t
Answer: Option
Explanation:

= 0 - (-e-t) = e-t.


42.
Given , and f(t)t → ∞ is . The value of k is
3/16
16/3
3
1/4
Answer: Option
Explanation:

.


43.
In a one port network . It is excited by a unit step current. The initial and final values of voltage across the network impedance are
1 and 0
Answer: Option
Explanation:


44.
In the circuit of figure, the current through battery E2 is
1 A discharging
1 A charging
9 A discharging
9 A charging
Answer: Option
Explanation:

1 A current is flowing into the battery. Therefore, it is charging current.


45.
In figure, the current supplied by battery at t = 0.5s is
1.1 A
1.9 A
0
1.632 A
Answer: Option
Explanation:

Time constant of R-L branch = = 0.5 seconds. Current in 6Ω resistance is 1 A and current in R-L branch is 63.2% of final current of 1 A.