Electronics and Communication Engineering - Networks Analysis and Synthesis
Exercise : Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 27
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 2
26.
In the circuit of figure
Answer: Option
Explanation:
Voltage across inductance leads the current and voltage across resistance is in phase with the current.
27.
Two capacitors of 16 μF each are connected in series. Another capacitor of 16 μF is connected in parallel with this combination. The total capacitance will be
48 μF
32 μF
24 μF
Answer: Option
Explanation:
28.
Assertion (A): Operator has a value 1 ∠ - 90° or 1 ∠ 90°.
Reason (R): Operator 'a' has a value 1 ∠ 120°.
Answer: Option
Explanation:
j = 1∠90°.
29.
The maximum current and voltage ratings for a 0.5 W, 10 kW resistor are
Answer: Option
Explanation:
.
30.
Figure shows a pole zero plot of I(s). The likely current response in time domain is
Answer: Option
Explanation:
Therefore , i(t) = -e-t + 2e-2t
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