Electronics and Communication Engineering - Networks Analysis and Synthesis
Exercise : Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 27
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 2
46.
In figure, a voltmeter of internal resistance 1200 Ω is connected across 600 Ω resistance and it reads 5 V. The value of R is
Answer: Option
Explanation:
47.
For the wave shown in figure, the average and rms values are
Answer: Option
Explanation:
Area of triangle is half of rectangle. So average value = 0.5 x 100 = 50 A.
48.
A 10 ohm resistance and a 10 ohm capacitor are connected in series across a 100 V ac supply. The rms voltage across resistance is
1002V
100 V
none of the above
Answer: Option
Explanation:
49.
When a 10 K, 10%, 1/4 Ω resistor is connected in series with a 12 K, ± 1%, 1/4 Ω resistor, the resulting combination has the following specifications
Answer: Option
Explanation:
Req = R1 + R2, 
maximum.
50.
The resonance frequency of the circuit is
Answer: Option
Explanation:
Leq = 2 + 2 + 2 
6 mH
.
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