Electronics and Communication Engineering - Networks Analysis and Synthesis

16.
In figure, the voltage V1 = 4∠0 V. The source voltage V2 is
8 - j8 volts
4 - j4 volts
8 - j4 volts
8 - j16 volts
Answer: Option
Explanation:

IR = 2∠OA, I1 = 2∠-90° = -j 2A.

Total current = 2 - j2.

V2 = 2 (2 - j2) + 4∠0 = 8 - j4 volts.


17.
A capacitor whose capacitance Ct = C0 (1- cos ωt) is fed by a sinusoidal voltage v = V0 sin ωt. The equation for current i is
ω C0V0 cos ωt
ω C0V0 sin ωt
ω C0V0 (cos ωt - cos2 ωt)
none of the above
Answer: Option
Explanation:

i = or i = C0 (1 - cos ωt) ωV0 cos ωt = C0ωV0 (cos ωt - cos2 ωt)


18.
Figure shows an RC circuit. The magnitude plot V2/V1
will rise exponentially to R2/(R1 + R2) as ω → ∞
will rise linearly to R2/(R1 + R2) as ω → ∞
will decrease to zero as ω → ∞
will rise 1 at ω = 0 and then decrease as ω → ∞
Answer: Option
Explanation:


19.

Assertion (A): In a circuit having high inductance, reactive power may be more than apparent power.

Reason (R): Reactive power = VI sin θ.

Both A and R are true and R is correct explanation of A
Both A and R are true and R is not the correct explanation of A
A is true but R is false
A is false but R is true
Answer: Option
Explanation:

Reactive power cannot be more than apparent power.


20.
A two branch parallel circuit has a 10 Ω resistance and 0.5 H inductance in one branch and a 100 μF capacitor in the second branch. It is fed from 100 V ac supply. At resonance, the source current is
10 A
1 A
0.2 A
0.05 A
Answer: Option
Explanation:

At parallel resonance source current =