Electronics and Communication Engineering - Networks Analysis and Synthesis - Discussion
Discussion Forum : Networks Analysis and Synthesis - Section 7 (Q.No. 16)
16.
In figure, the voltage V1 = 4∠0 V. The source voltage V2 is
Answer: Option
Explanation:
IR = 2∠OA, I1 = 2∠-90° = -j 2A.
Total current = 2 - j2.
V2 = 2 (2 - j2) + 4∠0 = 8 - j4 volts.
Discussion:
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