Electronics and Communication Engineering - Networks Analysis and Synthesis
Exercise : Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 27
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 2
46.
In a linear circuit, the superposition principle can be applied to calculate the
Answer: Option
Explanation:
Apply KVL
(4 - I) 10 + 4 (9 - I) = 5 I
I = 4A
P = I2.R 80 W.
47.
If A = 7 ∠15, A2 is
Answer: Option
Explanation:
48.
The colour coding of a resistors shows 100 K, ± 10%. When the resistance was measured with an ohmmeter, it read
Answer: Option
Explanation:
Ohmmeter measured 100 K ± 10/2 95 Ω.
49.
The output voltage of a charger is
Answer: Option
Explanation:
The charger has to supply current to battery for charging. This is possible only if voltage of charger is more than that of battery.
50.
The circuit in figure has reached steady values with switch open. If switch is closed at t = 0 the voltage across 2 μF capacitance at t = 0+ is
Answer: Option
Explanation:
At t = 0-, VC = 0 and voltage across a capacitor cannot change instantaneously.
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