Electronics and Communication Engineering - Networks Analysis and Synthesis
Exercise : Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 14
- Networks Analysis and Synthesis - Section 27
- Networks Analysis and Synthesis - Section 26
- Networks Analysis and Synthesis - Section 25
- Networks Analysis and Synthesis - Section 24
- Networks Analysis and Synthesis - Section 23
- Networks Analysis and Synthesis - Section 22
- Networks Analysis and Synthesis - Section 21
- Networks Analysis and Synthesis - Section 20
- Networks Analysis and Synthesis - Section 19
- Networks Analysis and Synthesis - Section 18
- Networks Analysis and Synthesis - Section 17
- Networks Analysis and Synthesis - Section 16
- Networks Analysis and Synthesis - Section 15
- Networks Analysis and Synthesis - Section 1
- Networks Analysis and Synthesis - Section 13
- Networks Analysis and Synthesis - Section 12
- Networks Analysis and Synthesis - Section 11
- Networks Analysis and Synthesis - Section 10
- Networks Analysis and Synthesis - Section 9
- Networks Analysis and Synthesis - Section 8
- Networks Analysis and Synthesis - Section 7
- Networks Analysis and Synthesis - Section 6
- Networks Analysis and Synthesis - Section 5
- Networks Analysis and Synthesis - Section 4
- Networks Analysis and Synthesis - Section 3
- Networks Analysis and Synthesis - Section 2
31.
In the series circuit shown in figure, for series resonance, the value of the coupling coefficient, K will be
Answer: Option
Explanation:
Mutual inductance wm = ωk L1L2
m = k. 2. 8j2 = 4k. j
Z = 20 - j10 + j2 + j6 + 2.4kj - 2j + 8kj = 0 at resonance
-2 = -8k
k = 1/4 0.25 .
32.
The degree of the nodes 1, 2, 3, 4 is
Answer: Option
Explanation:
Degree of node is the no.of branch incident to it.
33.
In an RC series circuit R = 100 Ω and XC = 10 Ω. In this circuit
Answer: Option
Explanation:
In RC circuit the current leads the voltage. 
34.
The impedance of an RC series circuit is 12 Ω at f= 50 Hz. At f= 200 Hz, the impedance will be
Answer: Option
Explanation:
Z = R2 + XC2. When f is made four times, XC becomes one-fourth but R remains the same.
35.
A current is flowing through a conductor with non-uniform area of cross-section. Then
Answer: Option
Explanation:
Current density = current/area of cross-section. Same current throughout the conductor.
Since, area of cross-section is non-uniform, current density will be different at different cross-sections.
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