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Electronics and Communication Engineering - Exam Questions Papers

Exercise : Exam Questions Papers - Exam Paper 11
26.
A function n(x) satisfied the differential equation where L is a constant. The boundary
conditions are: n(0) = K and n(∞) = 0. The solution to this equation is
n(x) = K exp(x/L)
n(x) = K exp (-x/L)
n(x) = K2 exp (-x/L)
n(x) = K exp (-x/L)
Answer: Option
Explanation:

n(∞) = 0, ∴ B = 0, n(0) = k ∴ B = k.

27.
If over the path shown in the figure is
0
1
23
Answer: Option
Explanation:

.

28.
50 independent low pass signals of bandwidth W, 2W, 3W, W, 2W, 3W, W, 2W, 3W Hz are to be time division multiplexer on a common channel using PAM. To achieve this, the minimum transmission capacity of the channel should be __________ .
1 Hz
12 Hz
3 Hz
6 Hz
Answer: Option
Explanation:

The commulator in TDM has to rotate at a speed twice that of highest bandwidth 3W x 2 = 6W Hz.

∴ Channel capacity = 2B = 2(6 W) = 12 W Hz.

29.
Find the value of K for which Vy = 0
Answer: Option
Explanation:

30.
Two coils X of 1000 turns and Y of 2000 turns are placed such that 60% of the flux produced by coil X links coil Y. A current of 1 A in coil X produces 0.1 wb flux. The mutual inductance between coils is
0.12 H
0.08 H
0.06 H
0.04 H
Answer: Option
Explanation:

L2 = 0.1 X 4 = 0.4

M = kL1L2 = 0.6 0.4 X 0.1

= 0.6 X 0.2 = 0.12 .

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