Electronics and Communication Engineering - Exam Questions Papers
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16.
A conductor in x-y plane and having length 1 m is moving with a velocity V = (2i + 3j + k) m/sec. A magnetic induction field B = (i + 2j) Wb/m2 is applied to the conductor. The potential difference between the ends of the conductor is
Answer: Option
Explanation:
= - (V x B) = - (2i + 3j + k) x (i + 2j)
∴ || = (E2x + E2y + E2z) = 6 v/m
∴ Potential Difference across 1 m length = 6.
17.
A 1000 kHz carrier wave modulated 40% at 4000 Hz is applied to a resonant circuit tuned to a carrier frequency and having Q = 140. What is the degree of modulation after passing the wave through this circuit?
Answer: Option
Explanation:
Resulting depth of modulation is given by :
when δ =
fc = 1000 x 103 Hz
fm = 4 x 103 Hz
δ =
m0 =
= = 0.27 .
18.
The VTH at terminals A and B is equal to,


Answer: Option
Explanation:
Apply KVL to loop 1
5V - 3I1 - 2(I1 - I2) - 5V = 0
∴ I2 = 0
5 - 3I1 - 2I1 - 5V = 0
∴ I1 = 0
∴ VAB = 5V.
19.
If
, then y has a

Answer: Option
Explanation:
.
20.
If
. dt, then F[y(t)] is

Answer: Option
Explanation:
⇒ F{Y(t)} = Y(f) = X(f) x
sin (t) ⇌
By duality :⇌ sgn + (- f)
⇒ ⇌ jsgn (- f)
∴⇌ - j sgn (f)
∵ sgn(- f) = - sgn(f)
⇒ Y(f) = X(f). [- j sgn(f)].
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