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Electronics and Communication Engineering - Exam Questions Papers

Exercise : Exam Questions Papers - Exam Paper 9
31.
The function shown in figure, can represent a probability density function for A __________ .
A = 1/4
A = 1/6
A = 1/8
A = 1/2
Answer: Option
Explanation:

The condition for the probability density of function d(x) is f(x)dx = 1 and is always non negative or the area under the curve f(x) is unity.

⇒ A x 6 + x 2 x 2A = 1

or 8A = 1, or A = .

32.
For the circuit shown in figure below, the initial conditions are zero, its transfer function H(s) = is :
Answer: Option
Explanation:

.

33.
For the two-port network shown below, the short circuit admittance parameter matrix is
Answer: Option
Explanation:

34.
The circuit given below:

If R1 = R2 = 20 kΩ and C1 = 0.2 μF and C2 = 0.005 μF. Then which of the given statements given below is true?
Circuit is band stop with two edge frequency of 39.7875 Hz to 1592 Hz
Circuit is band pass with two edge frequency of 39.7875 Hz to 1592 Hz
Circuit is oscillator, oscillation at two frequencies 39.7875 Hz to 1592 Hz depending on R3, R4, R5 and R6
None of these
Answer: Option
Explanation:

= 39.7875 Hz.

= 15.92 Hz.

35.
The Nyquist sampling rate for the signal s(t) = is given by
400 Hz
600 Hz
1200 Hz
1400 Hz
Answer: Option
Explanation:

fs = 2fm

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