IndiaBIX

Electronics and Communication Engineering - Exam Questions Papers

Exercise : Exam Questions Papers - Exam Paper 9
6.
The depth of penetration at 4 MHz is 10 cm, then at 2.5 MHz it is
62.5 cm
13 cm
6.25 cm
8 cm
Answer: Option
Explanation:

Depth of penetration

δ2 = 12.64 cm.

7.
The expression given is F(A, B , C, D, E, F, G, H) = (33, 48, 102, 158, 222, 229, 233, 243, 255); then the __________ and __________ minterms are grouped together into dual and variable __________ is reduced using the dual
243, 233, D
222, 158, B
243, 255, A
229, 243, E
Answer: Option
Explanation:

We use Quine - McCluskey method of reduction :

We can observe that minterms 158 and 222 can be grouped together to reduce the variable 'B'.

8.
Calculate i(t) for t ≥ 0 assuming the switch has been in position A for a long time. At t = 0, the switch is moved to position B.
Answer: Option
Explanation:

9.
A source produces 4 symbols with probabilities , , , For this source, a practical coding scheme has an average codeword length of 2 bits/symbol. The efficiency of the code is
1
Answer: Option
Explanation:

Total information for L message is

Efficiency =.

10.
A generator of 50 Ω internal impedance and operating at 1 GHz feeds a 75 Ω load via a coaxial line of characteristic impedance 50 Ω. The VSWR on the feed line is
0.5
1.5
2.5
1.75
Answer: Option
Explanation:

ZL = 75 Ω

Zo = 50 Ω

∴ Reflection coefficient:

∴ .

Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers