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Electronics and Communication Engineering - Exam Questions Papers

Exercise : Exam Questions Papers - Exam Paper 6
41.
Time domain equivalent circuit of the figure is
None of the above
Answer: Option
Explanation:

In the left hand loop (- i1) enters the dot end while for the right handed loop i2 enters the dot end.

This will make both the M terms at first of + ve sign but as i1 = - ve hence ultimately the M term of right hand loop involving i1 = - ve.

V1 = - L1 + M

V2 = L2 - M .

42.
Locus of a point Z satisfying the equation arg is:
Straight line with equation y = x - 3
Circle with equation x2 + y2 - 3x + 3y = 0
Hyperbola with equation x2 - y2 - 3x - 3y - 2yx = 0
None of these
Answer: Option
Explanation:

Solving this further we will get x2 + y2 - 3x + 3y = 0 which is the equation of circle.

43.
A silicon PN junction with no bias have a doping concentration of
Nd = 2 x 1016 cm-3 and Na = 1016 cm-3. The space charge width is:
3.345 x 10-3 cm
3.345 x 10-4 cm
3.345 x 10-5 cm
3.345 x 10-6 cm
Answer: Option
Explanation:

w = 3.345 x 10-5 cm.

44.
In 8085, Whenever a signal is received at TRAP terminal its program execution is transferred to a subroutine on address __________ .
0000 H
0024 H
002 CH
provided by the address generation logic
Answer: Option
Explanation:

TRAP is considered to be of the highest priority and the address of the subroutine is given by 0024 H.

45.
If (225)Y = (165)8 find value of Y
7
8
9
11
Answer: Option
Explanation:

(225)y => 2Y2 + 2Y + 5 = (165)8 => (117)10

∴ 2Y2 + 2Y + 5 = 117

Y2 + Y - 56 = 0

∴ Y = 7 or Y = - 8

∴ Y should be 7.

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