Electronics and Communication Engineering - Exam Questions Papers

Number of forward paths K = 3

T₁ = G₁G₂G₃G₄

T₂ = G₁G₆G₄

T₃ = G₁G₇

Number of loops

L₁ = G₂H₁

L₂= G₅

Δ = 1 - [L₁ + L₂] + [L₁ L₂]

= 1 - [G₂H₁ + G₅] + [G₂G₅H₁]

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Statement 2 is false because maximum energy of photons varies linearly with frequency of incident light. It can be shown as follows

Photocurrent Vs Anode voltage with frequency and incident light as parameter the light intensity is constant.

F[x(t)] = X(f)

X(f) = x(t).e^{- jpft}.dt

From above expression, the unit of x(t) x e^-j2pft is volts and that of dt is seconds.

At f = 1 KHz

Similarly for 10 kHz,

The ampere's law is given as

∇.H = J

Taking divergence on both sides

∇.(∇xH) = ∇.J

i.e., ∇.(∇xH) = ∇.J = 0

∴ divergence of curl is always zero

But ∇.J = -r_v ... continuity equation.

Hence the inconsistency. It can be removed as follows

→

Let ∇ x H = J + G where G is some unknown quality.

Then ∇.(∇ x H) = ∇.(J x G) = 0

i.e. ∇.J + ∇.G = 0

i.e. ∇.J = -∇.G

or ∇.G = (-r_v)

i.e. ∇.G = r_v ...... Gauss's law in point form

Differentiating on both sides.

∇.D = r_v

Comparing (i) and (ii), G = D

Thus ∇ x H = J + D

Where J is conduction current density and D is displacement current density which is added to remove the inconsistency of Ampere's law.