Electronics and Communication Engineering - Exam Questions Papers

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Minimum phase

H(z) = 6 + z^-1 - z^-1

6z² + z - 1 = 0

∴ We have zeros at z = 1/3 and z = - 1/2

∴ All the zeroes lies inside the unit circle, it is a min. phase system.

Now E = -∇V

E = ∇V

At r = 2, θ = p/2; Φ = 0 we have

∴ D = 22.12 PC/m².

Now it is evident from the truth tables that sum and differennce are same.

For finding Thevenin equivalent

Short voltage source

Open circuit source

Now Thevenin equivalent

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