Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion

Discussion Forum : Electronic Devices and Circuits - Section 2 (Q.No. 14)
14.
From the given circuit below, we can conclude that.
BJT is pnp
BJT is npn
transistor is faulty
not possible to determined
Answer: Option
Explanation:

According to figure, both the LED is glowing, which indicate that circuit is complete in both the half cycle of a.c. signal.

Therefore Emitter and Base junction will act as short circuit in both direction, which indicate transistor is faulty.

Discussion:
2 comments Page 1 of 1.

Durgesh kr said:   7 years ago
Both the led is flowing that means emitter and base junction will be shorted hence it is the faulty condition Ac to fig.

Dolon said:   8 years ago
Can anyone please explain this?

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