Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 2 (Q.No. 44)
44.
The Hall constant in Si bar is given by 5 x 103 cm3/ coulomb, the hole concentration in the bar is given by
Answer: Option
Explanation:
.
Discussion:
3 comments Page 1 of 1.
Kiran said:
4 years ago
Rh = 5 x 10^3 cm3/coulomb.
e = Electron charge = 1.602176634 * 10^19 coulomb.
e = Electron charge = 1.602176634 * 10^19 coulomb.
Ankita said:
7 years ago
How it came? Can you please explain.
Manoj Bhardwaj said:
8 years ago
p = 1/5*103 * 1.6 10-19,
10/8 *10^15,
1.25*10^15.
10/8 *10^15,
1.25*10^15.
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