Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion

Discussion Forum : Electronic Devices and Circuits - Section 2 (Q.No. 34)
34.
A diode is operating in forward region and the forward voltage and current are v = 3 + 0.3 sin ωt (volts) and i = 5 + 0.2 sin ωt (mA). The average power dissipated is
15 mW
about 15 mW
1.5 mW
about 1.5 mW
Answer: Option
Explanation:

The contribution of sine terms to power dissipation is zero.

Discussion:
5 comments Page 1 of 1.

Rohan said:   1 decade ago
As the contribution of sine terms to power dissipation is zero and P = v*i.

Karthik said:   9 years ago
According to me, the answer is A) 15 mW.

Asda said:   9 years ago
@Karthik . Please explain how its A) 15mW.

Ram said:   8 years ago
How sin terms to power dissipation is zero?

Ajax said:   6 years ago
Average of sin(x) is zero.

V(ave) = (1/(2π)) Int[ sin(x),0,2π] = 0.

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