Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 4 (Q.No. 48)
48.
In a reverse biased p-n junction, the reverse bias is 4V. The junction capacitance is about
Discussion:
7 comments Page 1 of 1.
Kyle said:
9 months ago
Here’s the equation in a simple copy-paste format:
Csubj = Csub0/sqrt(1 + Vsubr/Vsub0).
Given:
Vr = 4V (reverse bias).
V0 ≈ 0.7V (built-in potential for silicon).
Since junction capacitance decreases with increasing reverse bias, the expected value is 20 pF.
Final Answer: 20 pF.
Csubj = Csub0/sqrt(1 + Vsubr/Vsub0).
Given:
Vr = 4V (reverse bias).
V0 ≈ 0.7V (built-in potential for silicon).
Since junction capacitance decreases with increasing reverse bias, the expected value is 20 pF.
Final Answer: 20 pF.
Nevada said:
4 years ago
Please explain it in detail.
Nivedha said:
7 years ago
Actually, we can guess the answer. Junction capacitance is inversely proportional to reverse voltage. Here reverse voltage is more so capacitance has to be less.
(2)
Miles Carlson said:
8 years ago
How did this happen? please explain.
Mukund said:
9 years ago
Anyone please explain it.
Hari charan said:
9 years ago
Explanation please.
Syam krishnan b said:
10 years ago
How it comes please explain?
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