Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 5 (Q.No. 19)
19.
The rating of a transformer to deliver 100 watts of D.C. power to a load under half wave rectifier will be nearly
Discussion:
5 comments Page 1 of 1.
JRAJ said:
3 years ago
You are right @Kiran.
(1)
Kiran said:
4 years ago
TUF of HW rectifier is 0.287. 100/0.287 = 348.43 ~ 350VA.
(2)
Pallavi said:
5 years ago
Why that's 0.287? Please explain.
(1)
Mahesh raj said:
7 years ago
TUF = dc load power/ac load power * 100,
(100/.287) * 100 = 348.7~350.
(100/.287) * 100 = 348.7~350.
(1)
Ajith b nair ( Ajit) said:
9 years ago
Efficiency = dc load power/ac load power.
The efficiency of HWR is 40.2%.
So, 0.402=100/ac load power.
AC load power = 100/.402 = 248.6 watt.
So, may the answer is not 350, may have a chance of 250 W think am.
Sorry if am wrong.
The efficiency of HWR is 40.2%.
So, 0.402=100/ac load power.
AC load power = 100/.402 = 248.6 watt.
So, may the answer is not 350, may have a chance of 250 W think am.
Sorry if am wrong.
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