Electronics and Communication Engineering - Electronic Devices and Circuits - Discussion
Discussion Forum : Electronic Devices and Circuits - Section 8 (Q.No. 48)
48.
For a BJT, under the saturation condition,
Discussion:
1 comments Page 1 of 1.
Nikunj said:
8 months ago
For Active Region.
Emitter Junction(Je) is Forward Biased and the Collector Junction is Reversed Biased(Jc).
Therefore Ic= a*Ie and Ic = B * Ib.
For the Saturation region,
Both Je and Jc are Forward-biased.
Therefore Ic(saturation)< = aIe and Ic(saturation)<=BIb.
The corresponding saturation voltages are,
Vbe(sat) = 0.8 volts,
Vce(sat) = 0.2 volts,
Vcb(sat) = -0.6 volts.
For the Cutt Off region;
Both Je and Jc are Reverse-biased
Therefore Ib = Ic = Ie = 0.
Emitter Junction(Je) is Forward Biased and the Collector Junction is Reversed Biased(Jc).
Therefore Ic= a*Ie and Ic = B * Ib.
For the Saturation region,
Both Je and Jc are Forward-biased.
Therefore Ic(saturation)< = aIe and Ic(saturation)<=BIb.
The corresponding saturation voltages are,
Vbe(sat) = 0.8 volts,
Vce(sat) = 0.2 volts,
Vcb(sat) = -0.6 volts.
For the Cutt Off region;
Both Je and Jc are Reverse-biased
Therefore Ib = Ic = Ie = 0.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers