Electronics and Communication Engineering - Digital Electronics - Discussion
Discussion Forum : Digital Electronics - Section 1 (Q.No. 12)
12.
In the expression A + BC, the total number of minterms will be
Answer: Option
Explanation:
The min terms are ABC + ABC + AB C + ABC + ABC.
Discussion:
30 comments Page 1 of 3.
Dhammapriya said:
7 years ago
First of all, we need to convert a given logical expression into the standard form for minterms called canonical form. Ex. A+BC = A(B+B')(C+C') + BC(A+A').
Now solve this expression with the help of Boolean Laws you will arrive at A+BC = ABC + ABC' + AB'C + AB'C' + A'BC.
Now solve this expression with the help of Boolean Laws you will arrive at A+BC = ABC + ABC' + AB'C + AB'C' + A'BC.
(21)
Cherish said:
5 years ago
@Mohiyuva it's all about "and gate" & "or gate".
Truth Table:
A -- B -- C -- Output
0 -- 0 -- 0 -- F
0 -- 0 -- 1 -- F
0 -- 1 -- 0 -- F
0 -- 1 -- 1 -- T
1 -- 0 -- 0 -- T
1 -- 0 -- 1 -- T
1 -- 1 -- 0 -- T
1 -- 1 -- 1 -- T.
5 true. So 5 minterm.
Truth Table:
A -- B -- C -- Output
0 -- 0 -- 0 -- F
0 -- 0 -- 1 -- F
0 -- 1 -- 0 -- F
0 -- 1 -- 1 -- T
1 -- 0 -- 0 -- T
1 -- 0 -- 1 -- T
1 -- 1 -- 0 -- T
1 -- 1 -- 1 -- T.
5 true. So 5 minterm.
(14)
Seetha kumari said:
9 years ago
How to find the minterm?
A + BC = A (B + B') (C + C') + BC (A + A').
= A (BC + BC '+ B'C + B'C') + BCA + BCA',
= ABC + ABC'+ AB'C + AB'C' + BCA + BCA',
= 2ABC + ABC' + AB'C + AB'C' + A'BC.
A + BC = A (B + B') (C + C') + BC (A + A').
= A (BC + BC '+ B'C + B'C') + BCA + BCA',
= ABC + ABC'+ AB'C + AB'C' + BCA + BCA',
= 2ABC + ABC' + AB'C + AB'C' + A'BC.
(3)
Aneesh.M said:
10 years ago
A+BC = A (B+B') (C+C') + BC (A+A').
= (AB+AB') (C+C') + ABC + A'BC.
= ABC + ABC' + AB'C + AB'C' + ABC + A'BC.
= ABC + ABC' + AB'C + A'BC' + A'BC.
Since (ABC + ABC = ABC).
Hence 5 minterms.
= (AB+AB') (C+C') + ABC + A'BC.
= ABC + ABC' + AB'C + AB'C' + ABC + A'BC.
= ABC + ABC' + AB'C + A'BC' + A'BC.
Since (ABC + ABC = ABC).
Hence 5 minterms.
(2)
Siva said:
1 decade ago
x+x* = 1.
(1)
Aparna said:
7 years ago
I can't understand in truth table form. So please explain it.
(1)
Padmaja said:
9 years ago
A B C BC A+BC
1 1 1 1 1
1 1 0 0 1
1 0 1 0 1
1 0 0 0 1
0 1 1 1 1
0 1 0 0 0
0 0 1 0 0
0 0 0 0 0
Write the expressions for true values i.e. for 1 values.
First five are true values.
ABC + ABC' + AB'C + AB'C' + A'BC.
1 1 1 1 1
1 1 0 0 1
1 0 1 0 1
1 0 0 0 1
0 1 1 1 1
0 1 0 0 0
0 0 1 0 0
0 0 0 0 0
Write the expressions for true values i.e. for 1 values.
First five are true values.
ABC + ABC' + AB'C + AB'C' + A'BC.
(1)
Diksha said:
8 years ago
Using k- map, it will be easy to solve these kind of problems.
(1)
RJ PHENOMENAL said:
8 years ago
We have to express it in standard form.
(1)
Adil Tanveer said:
7 years ago
If we obtain the minterm then how can we obtain max term?
Please, anyone explain it.
Please, anyone explain it.
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