Electronics and Communication Engineering - Digital Electronics - Discussion

Discussion Forum : Digital Electronics - Section 1 (Q.No. 12)
12.
In the expression A + BC, the total number of minterms will be
2
3
4
5
Answer: Option
Explanation:

The min terms are ABC + ABC + AB C + ABC + ABC.

Discussion:
30 comments Page 1 of 3.

Tarun said:   1 decade ago
How you found these minterms?

Selvi.M said:   1 decade ago
How to find minterms?

Anup said:   1 decade ago
Minterm is a product of literals which each input variable appears exactly one.

Kvrv said:   1 decade ago
A(B+B*)(C+C*) + BC(A+A*).

Priya said:   1 decade ago
Can anyone explain how we obtain the above expression?

Siva said:   1 decade ago
x+x* = 1.
(1)

Kalpish said:   1 decade ago
Please explain briefly.

Sharon said:   1 decade ago
In this we are using De Morgan's law.

i.e A+BC = A(B+B')+BC(A+A').

= AB+AB'+ABC+A'BC.

= AB(C+C')+AB'(C+C')+ABC+A'BC.

= ABC+ABC'+AB'C+AB'C'+ABC+A'BC.

= ABC+ABC'+AB'C+A'BC(ABC+ABC=ABC).

= 1+1+1+1+1 = 5 min terms.

So, the total no. of min terms are 5.

Aneesh.M said:   10 years ago
A+BC = A (B+B') (C+C') + BC (A+A').

= (AB+AB') (C+C') + ABC + A'BC.

= ABC + ABC' + AB'C + AB'C' + ABC + A'BC.

= ABC + ABC' + AB'C + A'BC' + A'BC.

Since (ABC + ABC = ABC).

Hence 5 minterms.
(2)

Deepak deshmukh said:   10 years ago
Simply draw this equation on truth table. You will get the answer.


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