Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 2)
2.
The turns ratio required to match an 80 source to a 320 load is
80
20
4
2
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
101 comments Page 4 of 11.

Pal said:   1 decade ago
N(s)/N(p) = E(S)/E(p)-1.

I(p) N(p) = I(s) N(p).

E(P) N(P) / R(P) = E(S) N(S)/R(S)-2.

From 1 and 2.

Sq (N(S)/N(P)) = R(s)/R(p).

Satya said:   1 decade ago
As in a transformer input power = output power i.e. energy is transformed, v1^2 / z1 = v2^2 /z2. hence turns ratio = sqrt(z2/z1)

Akash.bhure said:   1 decade ago
Source resistance(R1) = 80 ohms.

Load resistance(R2) = 320 ohms.

R1 = R2/K^2.
80 = 320/K^2.
K^2 = 320/80 = 4.
K = sqrt(4) = 2.

K.Gopalakrishna said:   9 years ago
Transformation ratio k = n2/n1.
Here the given value is in ohms i.e resistive.
That will be more in the winding.
i.e 320/8 = 4.

PABAN said:   1 decade ago
We know in ideal Transformer v2/v1 = i1/i2 = k.

v2/v1 = (v1/r1)*(r2/v2).

(v2/v1)^2 = r2/r1.

After calculation result is 2.

Uma said:   1 decade ago
Turns ratio is directly proportional to square root of load impedance to source impedance i.e., here, sq root of 320/80=2.

Siva said:   1 decade ago
Transformer rating is in kVA because Cu loss depends on only voltage and current and it is independent of power factor.

Prafulla said:   8 years ago
If primary Resistance transfer to the secondary winding. Then,
R2=K^2 R1.
320=K^2 80,
K^2=320/80 = 4.
K= √4 = 2.

Ranjeet singh said:   1 decade ago
v2/v1 = i1/i2.

= v1/r1*r2/v2.

(v2/v1)^2 = r2/r1.

(k)^2 = r2/r1.

k^2 = 320/80.

k^2 = 4 .

k = 2.

Hritiks said:   3 years ago
v1*i1 = v2 * i2.

V1^2/ R1 = V2^2/R2.

V2^2 / V1^2 = R2/R1.
(k)^2 = r2/r1.
k^2 = 320/80.
k^2 = 4 .
k = 2.
(21)


Post your comments here:

Your comments will be displayed after verification.