Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 2)
2.
The turns ratio required to match an 80 
source to a 320 load is
source to a 320 load isDiscussion:
101 comments Page 1 of 11.
Hritiks said:
3 years ago
v1*i1 = v2 * i2.
V1^2/ R1 = V2^2/R2.
V2^2 / V1^2 = R2/R1.
(k)^2 = r2/r1.
k^2 = 320/80.
k^2 = 4 .
k = 2.
V1^2/ R1 = V2^2/R2.
V2^2 / V1^2 = R2/R1.
(k)^2 = r2/r1.
k^2 = 320/80.
k^2 = 4 .
k = 2.
(21)
Anonymous said:
4 years ago
V1 * I1 = V2 * I2.
v1 * V1/R1 = V2 * V2/R2,
V1 ^ 2 / R1 = V2 ^ 2/R2,
V1^2 / V2^2 = R1/ R2,
V1/V2 = √(R1/R2),
N1/N2 = √(80/320),
N1/N2 = 1/2 (Turns Ratio).
So, the Answer should be 1/2.
v1 * V1/R1 = V2 * V2/R2,
V1 ^ 2 / R1 = V2 ^ 2/R2,
V1^2 / V2^2 = R1/ R2,
V1/V2 = √(R1/R2),
N1/N2 = √(80/320),
N1/N2 = 1/2 (Turns Ratio).
So, the Answer should be 1/2.
(8)
Khanindra Kalita said:
4 years ago
Source to a 320 ohm, mean primary side resistance is 320, and secondary side resistance is 80 ohm.
Now ,
We know that,
R1 = R2 * (N1/N2)^2,
320 = 80 * (N1/N2)^2,
(N1/N2)^2 = 320/80 = 4,
N1/N2 = √4.
= 2.
Now ,
We know that,
R1 = R2 * (N1/N2)^2,
320 = 80 * (N1/N2)^2,
(N1/N2)^2 = 320/80 = 4,
N1/N2 = √4.
= 2.
(7)
Hamayat ullah said:
5 years ago
Turns ratio,n = NP/NS.
(1)
Sanchayan Singha Roy said:
5 years ago
Let, the impedance of the secondary side be Zs and that of primary is Zp.
So, the formula is, Zs = Zp* (N1/N2)^2.
now, we can say here is, sq. root(Zs/Zp)= N1/N2.
Therefore, N1/N2= √(320/80).
And Turns ratio = 2.
So, the formula is, Zs = Zp* (N1/N2)^2.
now, we can say here is, sq. root(Zs/Zp)= N1/N2.
Therefore, N1/N2= √(320/80).
And Turns ratio = 2.
(2)
Adarsh P K said:
6 years ago
Turns ratio = square root(Zs/Zp).
Jems said:
6 years ago
Thanks all for explaining.
Rakesh said:
6 years ago
Turn ratio = √(R2/R1).
= √(360/80),
= √4,
= 2.
= √(360/80),
= √4,
= 2.
(4)
Zoodee said:
7 years ago
It should be 1/2.
(1)
Ramesh Vankudothu said:
7 years ago
K2: R2%R1
K2: 320%80
K = √4 => i.e 2.
K2: 320%80
K = √4 => i.e 2.
(1)
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