Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 2)
2.
The turns ratio required to match an 80
source to a 320
load is


Discussion:
101 comments Page 1 of 11.
Jayakarthick said:
8 years ago
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Dr.G.Suresh Babu said:
1 decade ago
Transformer works on the principle of Faradays Laws of Electro Magnetic Induction; with mutual Induction concept.
By Ohms Law ;current I = V/Z.
V =supply voltage- bak EMF.
Impedence Z =R+jX.
Reactance X =2 Pi f L.
We know that incase of DC supply,frequency f is zero;no induced EMF because there is no change of flux with DC(Induced EMF e= N dq/dt;).
Current I =(supply voltage-back EMF)/R=j+ X.
Here, numerator increases(back EMF is Zero) and denominator decreases(as X=0 and R is very less);consequently I increases to a dangerous level leading to burning of winding's if it is not properly fused.
Hence DC supply should not be connected to Transformer ; in-case connected a mechanism should be made to switch ON and OFF frequently(like SCR).
By Ohms Law ;current I = V/Z.
V =supply voltage- bak EMF.
Impedence Z =R+jX.
Reactance X =2 Pi f L.
We know that incase of DC supply,frequency f is zero;no induced EMF because there is no change of flux with DC(Induced EMF e= N dq/dt;).
Current I =(supply voltage-back EMF)/R=j+ X.
Here, numerator increases(back EMF is Zero) and denominator decreases(as X=0 and R is very less);consequently I increases to a dangerous level leading to burning of winding's if it is not properly fused.
Hence DC supply should not be connected to Transformer ; in-case connected a mechanism should be made to switch ON and OFF frequently(like SCR).
Jayakarthick said:
8 years ago
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Ramakrishna18893 said:
1 decade ago
Source belongs to primary winding where as load belongs to secondary winding. So in order to match or transfer impedance from primary side to secondary, k^2 (turns ratio) should be multiplied with primary impedance, then it will be equated with secondary impedance (matching is to obtain maximum power transfer). This is as illustrated.
80*k^2 = 320.
k^2 = 4.
k = 2.
In case transfer from secondary to primary, secondary impedance must be multiplied with 1/k^2. Equate it to primary impedance for matching. Same result will be obtained.
80*k^2 = 320.
k^2 = 4.
k = 2.
In case transfer from secondary to primary, secondary impedance must be multiplied with 1/k^2. Equate it to primary impedance for matching. Same result will be obtained.
Jayakarthick said:
8 years ago
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MB SHARON said:
8 years ago
The National Instructional Media Institute (NIMI) for Industrial Traning book.
Np/Ns=Zp/Zs.
Where,
Np=No of turns in the primary.
Ns=No of turns in the secondary.
Zp=primary impedance or (source).
Zs=secondary impedance or (load).
Sol; Source Z=80 ohm.
Load Z =320ohm.
Zp/Zs=80/320.
Turns Ratio =1:2 answer= 2.
1:2 Turns ratio match the 80 ohm source impedance to a 320 ohm load.
Np/Ns=Zp/Zs.
Where,
Np=No of turns in the primary.
Ns=No of turns in the secondary.
Zp=primary impedance or (source).
Zs=secondary impedance or (load).
Sol; Source Z=80 ohm.
Load Z =320ohm.
Zp/Zs=80/320.
Turns Ratio =1:2 answer= 2.
1:2 Turns ratio match the 80 ohm source impedance to a 320 ohm load.
Jayakarthick said:
8 years ago
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Hanumantha HK said:
9 years ago
Above all guys discussed ok but there is a mistake in that !
Turns ratio(n) = N1/N2 =V1/V2 = I2/I1.
Same Transformer ratio is (K) = 1/n.
Means V2/V1 = N2/N1 = I1/I2 = K.
The question is Turns Ratio ?
V1*I1=V2*I2.
(v1)^2/R1= (V2)^2/R2.
So (V1/V2)^2=R1/R2.
Turns ratio n = (N1/N2)^2=R1/R2=80/320=1/4.
When we make sqrt it will come = 1/2.
What you guys are saying the above solution ?
Turns ratio(n) = N1/N2 =V1/V2 = I2/I1.
Same Transformer ratio is (K) = 1/n.
Means V2/V1 = N2/N1 = I1/I2 = K.
The question is Turns Ratio ?
V1*I1=V2*I2.
(v1)^2/R1= (V2)^2/R2.
So (V1/V2)^2=R1/R2.
Turns ratio n = (N1/N2)^2=R1/R2=80/320=1/4.
When we make sqrt it will come = 1/2.
What you guys are saying the above solution ?
Prudhvi raj said:
1 decade ago
Source side will be taken as primary then r1=80 and we have to match to secondary(loadside) given that it is 320 ie r1'=320.
Actually we know that whenever primary referred to secondary,
r1'=ksquare*r1.
So here,
ksquare*r1 = 320 that implies that,
ksquare = 320/r1=320/80=4.
i.e., ksquare = 4 then k=2.
Here k = tranaformation ratio.
Actually we know that whenever primary referred to secondary,
r1'=ksquare*r1.
So here,
ksquare*r1 = 320 that implies that,
ksquare = 320/r1=320/80=4.
i.e., ksquare = 4 then k=2.
Here k = tranaformation ratio.
Jayakarthick said:
8 years ago
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