Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 2)
2.
The turns ratio required to match an 80
source to a 320
load is


Discussion:
101 comments Page 3 of 11.
Anonymous said:
4 years ago
V1 * I1 = V2 * I2.
v1 * V1/R1 = V2 * V2/R2,
V1 ^ 2 / R1 = V2 ^ 2/R2,
V1^2 / V2^2 = R1/ R2,
V1/V2 = √(R1/R2),
N1/N2 = √(80/320),
N1/N2 = 1/2 (Turns Ratio).
So, the Answer should be 1/2.
v1 * V1/R1 = V2 * V2/R2,
V1 ^ 2 / R1 = V2 ^ 2/R2,
V1^2 / V2^2 = R1/ R2,
V1/V2 = √(R1/R2),
N1/N2 = √(80/320),
N1/N2 = 1/2 (Turns Ratio).
So, the Answer should be 1/2.
(8)
Dorsing said:
8 years ago
Given that,
R1=80 ohm
R2=320 ohm
Transformer Ratio,
K = N1/N2 = V1/V2=R2/R1=I2/I1.
K=R2/R1.
= 320/80=4.
R1=80 ohm
R2=320 ohm
Transformer Ratio,
K = N1/N2 = V1/V2=R2/R1=I2/I1.
K=R2/R1.
= 320/80=4.
Anil Kumar said:
1 decade ago
As we know that V2/V1 = N2/N1 = I1/I2 = k.
So, V2/V1 = (V1/R1)*(R2/V2) = k.
=> (V2/V1)2 = R2/R1 = k.
Therefore, turns ratio(k) = sq. root of (R2/R1)
= sq. root of (320/80)
= 2.
So, V2/V1 = (V1/R1)*(R2/V2) = k.
=> (V2/V1)2 = R2/R1 = k.
Therefore, turns ratio(k) = sq. root of (R2/R1)
= sq. root of (320/80)
= 2.
Gopinadh puvvada said:
1 decade ago
Assuming the transformer to be ideal,as losses in primary and secondary are equal.
(I1)^2/R1=(I2)^2/R2.
(I1/I2)^2=R2/R1.
I1/I2=SQRT(320/80).
I1/I2=2.
So the answer is 2.
(I1)^2/R1=(I2)^2/R2.
(I1/I2)^2=R2/R1.
I1/I2=SQRT(320/80).
I1/I2=2.
So the answer is 2.
Haji Bilal said:
9 years ago
Hello, @Yash.
It should require to measure current and voltage of transformer from the secondary side. Then you will able to know KVA rating of the transformer!
It should require to measure current and voltage of transformer from the secondary side. Then you will able to know KVA rating of the transformer!
Surinder Rajput said:
8 years ago
Here is the little formula for impedance VS turns.
a= Turns Ratio, (Np/Ns)=Square Root of (Zp/Zs),
Square root of (380/20)=4/1,
Square root of (4/1)=2,
So 2.
a= Turns Ratio, (Np/Ns)=Square Root of (Zp/Zs),
Square root of (380/20)=4/1,
Square root of (4/1)=2,
So 2.
Ramm said:
1 decade ago
Transformer rating is KVA, because iron&Cu losses depending upon the voltage and current only. Then not depending in the pf so its calls kva only.
Siva said:
1 decade ago
In transformers we use the 50hz, because of how much of load is given it will be operated at the same frequency so that we use the constant.
Pruthibiraj gouda said:
1 decade ago
Here r1=80ohm, r2=320 ohm
we know v2/v1=i1/i2
v2/v1=v1/r1*r2/v2
=> k=(v1/v2)*(r2/r1)
=> k=1/k*(320/80)
=>K sq=4
k=2
Ans=2
we know v2/v1=i1/i2
v2/v1=v1/r1*r2/v2
=> k=(v1/v2)*(r2/r1)
=> k=1/k*(320/80)
=>K sq=4
k=2
Ans=2
Arun Kumar Raju C said:
1 decade ago
The turns ratio of a transformer is defined as the number of turns on its secondary divided by the number of turns on its primary.
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