Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 2)
2.
The turns ratio required to match an 80 source to a 320 load is
80
20
4
2
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
101 comments Page 5 of 11.

Ashu said:   1 decade ago
What is the actual formula for turns ratio is it K=N1/N2 OR K=N2/N1 & what is transformation ration?

PALIVELA VARAPRASAD said:   1 decade ago
v1xi1=v2i2
v1=cxn1
v2=cxn2
i1=v1/r1
i2=v2/r2
so
(n2/n1)2=(r2/r1)
Hence turns ratio n2/n1=root(4)=2

Shajeer said:   1 decade ago
Turns Ratio = sqrt.(r2/r1)
= sqrt (320/80)
= sqrt (4)
= 2

K.gopala krishna said:   9 years ago
Here the value is in ohms.
i.e resistive
It will be more in winding.
n2/n1 = k,
320/80 = k,
= 4.

Rangaswamy M.D said:   1 decade ago
v2/v1 = i1/i2.
= v1/r1*r2/v2.
(v2/v1)^2 = r2/r1.

(k)^2 = r2/r1.
k^2 = 320/80.
k^2 = 4 .
k = 2.

Amjad moawia said:   9 years ago
No! @Hanumantha Hk.

The correct law is : vs/sp = NS/NP = IP/IS.

Please, revise once again.

Saheb said:   1 decade ago
R(hv) = K^2*R(lv).

[v2/v1 = k,i2*r2/i1*r1 = k, R(hv)/R(lv) = k^2; k = 2; r2/r1 = k^2].

Zeeshan said:   1 decade ago
If the above statment true that turn ratio is equal to load /source then answer comes 2.

Hemant said:   8 years ago
Can anyone give formula derivation for showing turns ratio in terms of resistance?

Rakesh said:   7 years ago
Turn ratio = √(R2/R1).
= √(360/80),
= √4,
= 2.
(4)


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