Electrical Engineering - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 1)
1.
The internal resistance of a 20,000 ohm/volt voltmeter set on its 5 V range is
20,000
100,000
200,000
1,000,000
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
32 comments Page 2 of 4.

Arun Sankar said:   1 decade ago
Ms. Juilee,

I have some doubt,

For finding I means, I=v/R.

But why your using this formula here IR*v.

Can you explain?

YoungLove said:   8 years ago
Internal resistance is given by Sensivity (20,000) * scale deflection (5)
Which is 20,000 * 5 = 100,000 ohms

Nazim uddin said:   1 decade ago
The internal resistant 20000 for 1 volt that = v = 5 and ohm law,
R = v*I 5*20000 = 100,000 ohm.

JUILEE said:   1 decade ago
According to me....
Internal resistance =20000ohm/v
voltage=5v
I.R.*V=20000*5
=100,000ohm

Deepak mohapatra said:   8 years ago
In 1volt resistance is 20000 Ω.
in 5volt =5 * 20000 = 100000 Ω.
(1)

LALITHA said:   1 decade ago
Given,

r = 20,000 ohms per volt.
For 1v r = 20,000.
For 5v R = 20,000*5 = 100,000.

Jyo said:   1 decade ago
According to ohm's law,

IR = 20,000ohm/volt.

V = 5v.

IR*V = 20,000*5 = 100000.

JUILEE MILIND GHATOLE said:   1 decade ago
Internal Resistance=20000ohm/V
Voltage=5v
I.R.*V=20000*5
=100,000ohm

Dinesh said:   1 decade ago
IR means Internal Resistance not current and resistance.

Junaid said:   9 years ago
Not understanding. Please explain me to get it.


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