Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 7)
7.
A 6.8 k resistor, a 7 mH coil, and a 0.02 F capacitor are in parallel across a 17 kHz ac source. The coil's internal resistance, RW, is 30 . The equivalent parallel resistance, Rp(eq), is
1,878
18,780
18,750
626
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
34 comments Page 3 of 4.

Swati arora said:   1 decade ago
I'm not getting the right answer.

My answer is 292.6 - 1173j after adding all components in parallel and taking w=106.8k.

Should I take w=17khz ?

Please help me out. It's so much time taking.

Krystina said:   1 decade ago
I am getting around the same answer as you: 294.2-1174j. Even if you use w = 17 kHz (leaving out the 2*pi) you still dont get it.

I got 34.6+122.4j. Not sure how they are getting this answer.

Sirisha said:   1 decade ago
1/Z=(1/R)+[1/(Rw+jXl)]+[1/jXc].

Is the above equation correct or did go wrong any where, because I got totally different answer. Please help me?

Sunil said:   1 decade ago
It is Resistance that has been asked for not impedance, in which case the answer should have been 29.9ohms.

Mrakovic said:   1 decade ago
Rp(eq) = Rw(Q^2+1).

Q = XL/Rw.

Pranoti said:   1 decade ago
I can not understand by this above solution. I want something simple and quickly under stable method. Please provide it.

Shrutali said:   1 decade ago
I'm not getting the answer. Please help me out.

Souma said:   1 decade ago
I need some quickly make out method, someone please help.

Rafi said:   1 decade ago
Can any one provide solution in detail? Please.

Mike said:   1 decade ago
This answer doesn't make any sense. How is the equivalent parallel resistance larger than the one resistor that is known, 6800?

If in parallel, it should be at least lower than 6800.


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