Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 7)
7.
A 6.8 k
resistor, a 7 mH coil, and a 0.02 
F capacitor are in parallel across a 17 kHz ac source. The coil's internal resistance, RW, is 30 . The equivalent parallel resistance, Rp(eq), is
resistor, a 7 mH coil, and a 0.02 F capacitor are in parallel across a 17 kHz ac source. The coil's internal resistance, RW, is 30 . The equivalent parallel resistance, Rp(eq), is1,878
18,780
18,750
626
Discussion:
34 comments Page 2 of 4.
Puja said:
9 years ago
@Mrakovic.
Can you tell me what is Q? And by using your formula I get an answer is 18660.192 but I have a confusion this answer is right or wrong.
Can you tell me what is Q? And by using your formula I get an answer is 18660.192 but I have a confusion this answer is right or wrong.
Bharath said:
9 years ago
Please show how to make the conversion without calculator.
Vani.c said:
9 years ago
Anyone please explain this problem with proper equation.
Likhitha said:
9 years ago
Anyone please tell me simplest and understandable answer.
Stuti kushwaha said:
9 years ago
Answer is not getting please help me.
Saurabh said:
10 years ago
We could find answer by conventional way but is there any shortcut to find quick answer as conventional way is highly time taking.
Manoj patil said:
10 years ago
Please give me right solution because I got totally wrong answer.
Ajit Kumar said:
1 decade ago
1/(Z-30) = 1/6.8 + J*.017*0.02 + 1/(J17*7).
Now Z can be calculated in form of 1/z = x + j Y.
Rp = 1/x.
Now Z can be calculated in form of 1/z = x + j Y.
Rp = 1/x.
Swapnil said:
1 decade ago
Please provide some description.
Pawan mahe. said:
1 decade ago
Consider internal resistance of coil with inductive reactance.
Z (L) =jX (L) +R (L).
And add all components in parallel now.
It's complex but you will get answer.
Z (L) =jX (L) +R (L).
And add all components in parallel now.
It's complex but you will get answer.
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