# Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 7)

7.

A 6.8 k resistor, a 7 mH coil, and a 0.02 F capacitor are in parallel across a 17 kHz ac source. The coil's internal resistance,

*R*, is 30 . The equivalent parallel resistance,_{W}*R*(eq), is_{p}Discussion:

34 comments Page 1 of 4.
DARSH said:
8 months ago

Here, we didn't find the equivalent resister of parallel circuit. Without resistor place in series with capacitor.

Mahe said:
12 months ago

I'm not getting it. Anyone, explain me the right answer.

Anomi said:
4 years ago

Please explain the solution.

Swathi said:
4 years ago

Can anyone explain me in detail please?

Muhammad said:
4 years ago

By using this equation1/Z=(1/R)2+(1/XL2-1/XC2)2 we get the answer.

Arunkumar said:
5 years ago

What is X value in G and J value in Y?

Please explain clearly.

Please explain clearly.

KONDAVENI SANTHOSH said:
5 years ago

It is for internal resistance present in the inductor and capacitor.

Genrally, we solve this problem in tank circuit model

XL=2*3.14*f*L.

Xc=1/(2*3.14*f*C).

After convert all parallel networks into conductance,suceptance,admitance values

Conductance(G)=(R)/(R^2 + X^2); R=30

In this scenario internal restance present in L&C.

so we are taking suceptance(B)=(X)/(R^2 + X^2); R=30.

Y=y1 + y2 + y3 Here, Y= admitance.

Y=G1+G2 + G3 + J(BL -Bc); G1 value take restor R1=6800 OHM; G2&G3 values take R=30.

After calculation,

Y=G + J(B),

finally R=1/G,

R=18,780 OHMS.

Genrally, we solve this problem in tank circuit model

XL=2*3.14*f*L.

Xc=1/(2*3.14*f*C).

After convert all parallel networks into conductance,suceptance,admitance values

Conductance(G)=(R)/(R^2 + X^2); R=30

In this scenario internal restance present in L&C.

so we are taking suceptance(B)=(X)/(R^2 + X^2); R=30.

Y=y1 + y2 + y3 Here, Y= admitance.

Y=G1+G2 + G3 + J(BL -Bc); G1 value take restor R1=6800 OHM; G2&G3 values take R=30.

After calculation,

Y=G + J(B),

finally R=1/G,

R=18,780 OHMS.

Rasel said:
5 years ago

Here, rp= (sq(Rw)+sq(Xl))/RW= 18665.

Revathi said:
5 years ago

I am not understanding please explain it.

Puja said:
6 years ago

@Mrakovic.

Can you tell me what is Q? And by using your formula I get an answer is 18660.192 but I have a confusion this answer is right or wrong.

Can you tell me what is Q? And by using your formula I get an answer is 18660.192 but I have a confusion this answer is right or wrong.

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