Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 7)
7.
A 6.8 k
resistor, a 7 mH coil, and a 0.02 
F capacitor are in parallel across a 17 kHz ac source. The coil's internal resistance, RW, is 30 . The equivalent parallel resistance, Rp(eq), is
resistor, a 7 mH coil, and a 0.02 F capacitor are in parallel across a 17 kHz ac source. The coil's internal resistance, RW, is 30 . The equivalent parallel resistance, Rp(eq), is1,878
18,780
18,750
626
Discussion:
34 comments Page 1 of 4.
Shrutali said:
1 decade ago
I'm not getting the answer. Please help me out.
Swapnil said:
1 decade ago
Please provide some description.
Pawan mahe. said:
1 decade ago
Consider internal resistance of coil with inductive reactance.
Z (L) =jX (L) +R (L).
And add all components in parallel now.
It's complex but you will get answer.
Z (L) =jX (L) +R (L).
And add all components in parallel now.
It's complex but you will get answer.
Swati arora said:
1 decade ago
I'm not getting the right answer.
My answer is 292.6 - 1173j after adding all components in parallel and taking w=106.8k.
Should I take w=17khz ?
Please help me out. It's so much time taking.
My answer is 292.6 - 1173j after adding all components in parallel and taking w=106.8k.
Should I take w=17khz ?
Please help me out. It's so much time taking.
Krystina said:
1 decade ago
I am getting around the same answer as you: 294.2-1174j. Even if you use w = 17 kHz (leaving out the 2*pi) you still dont get it.
I got 34.6+122.4j. Not sure how they are getting this answer.
I got 34.6+122.4j. Not sure how they are getting this answer.
Sirisha said:
1 decade ago
1/Z=(1/R)+[1/(Rw+jXl)]+[1/jXc].
Is the above equation correct or did go wrong any where, because I got totally different answer. Please help me?
Is the above equation correct or did go wrong any where, because I got totally different answer. Please help me?
Sunil said:
1 decade ago
It is Resistance that has been asked for not impedance, in which case the answer should have been 29.9ohms.
Mrakovic said:
1 decade ago
Rp(eq) = Rw(Q^2+1).
Q = XL/Rw.
Q = XL/Rw.
Pranoti said:
1 decade ago
I can not understand by this above solution. I want something simple and quickly under stable method. Please provide it.
Ajit Kumar said:
1 decade ago
1/(Z-30) = 1/6.8 + J*.017*0.02 + 1/(J17*7).
Now Z can be calculated in form of 1/z = x + j Y.
Rp = 1/x.
Now Z can be calculated in form of 1/z = x + j Y.
Rp = 1/x.
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